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2018 NFL Draft Order: Buccaneers pick seventh

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The final draft order for 2018 is out.

NFL: Preseason-Washington Redskins at Tampa Bay Buccaneers Kim Klement-USA TODAY Sports

The 2017 NFL season is over, which means we know the order of the 2018 NFL draft. The Cleveland Browns will hold the first overall pick, what with them going 0-16 and all. The Tampa Bay Buccaneers will pick seventh, thanks to a 5-12 record and a tough strength of schedule.

The Bucs are tied at 5-11 with three other teams, but because they faced a tough slate of opponents they’ll pick after the Denver Broncos and New York Jets, who had easier schedules, but ahead of the Chicago Bears, who had an even tougher schedule.

Here’s the top 10 of 2018 NFL picks. You can find the full 2018 NFL draft order over at SB Nation.

1. Cleveland Browns (0-16)

2. New York Giants (3-13)

3. Indianapolis Colts (4-12)

4 Cleveland Browns (via Houston Texans, 4-12)

5. Denver Broncos (5-11)

6. New York Jets (5-11)

7. Tampa Bay Buccaneers (5-11)

8. Chicago Bears (5-11)

9. Cincinnatti Bengals (6-10)

t-10. San Francisco 49ers (6-10)

t-10. Oakland Raiders (6-10)