The Tampa Bay Buccaneers have their first award of the season: Bobby Rainey has been named the NFC Offensive Player of the Week for his performance against the Atlanta Falcons. The running back rushed for 163 yards on 30 carries, including two touchdown runs, and added two catches for four yards and his third touchdown on the day. It's the kind of dominant performance you don't see every day -- especially not out of a running back picked up off waivers just a few weeks earlier.
Rainey's performance helped the Bucs to their second win of the season and their first truly convincing game, albeit against a very weak opponent. Tampa Bay destroyed Atlanta, winning 41-20 in their first blowout win in over a year. They'll face a tougher test this weekend, though, as they travel to Detroit to take on the Lions and their explosive passing game. It's one thing to run all over the injury-depleted Falcons, and another entirely to take on a largely healthy (and winning) Detroit team.